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Atomic Physics Domain Guide

Atomic structure and spectra, X-rays and Bragg diffraction, solids and band structure, and nuclear binding and decay — the specialised block, unified by one constant and one habit: work in electronvolts and think in ratios.

Concise answer

This domain is the exam's specialised block: the structure of atoms, the spectra they emit, the solids they build, and the nuclei at their centres. It looks like four subjects, but the same two moves solve almost every item. First, a bound system has a discrete energy ladder, and a transition emits or absorbs a photon of exactly the level difference. Second, all the arithmetic collapses if you work in electronvolts and nanometres with hc=1240 eVnmhc = 1240\ \mathrm{eV\,nm}, because the questions are nearly always ratios or single divisions rather than genuine computations.

Definitions

Hydrogen-like atom
A nucleus of charge +Ze+Ze with exactly one electron. Its levels are En=13.6Z2/n2 eVE_n = -13.6Z^{2}/n^{2}\ \mathrm{eV} and its orbital radii are rn=n2a0/Zr_n = n^{2}a_0/Z with a0=0.0529 nma_0 = 0.0529\ \mathrm{nm}. Neutral helium or lithium is not hydrogen-like; He+\mathrm{He}^{+} and Li2+\mathrm{Li}^{2+} are.
Work function
The minimum energy needed to liberate an electron from a metal surface. Photons below that threshold energy eject nothing however intense the beam, which is the observation classical wave theory could not explain.
Characteristic and bremsstrahlung X-rays
An X-ray tube produces sharp characteristic lines from inner-shell transitions in the target, superposed on a continuous bremsstrahlung background that cuts off abruptly at λmin=hc/eV\lambda_{\min} = hc/eV, set by an electron converting all its kinetic energy into one photon.
Band gap
The energy interval between the filled valence band and the empty conduction band in a solid. A metal has none, a semiconductor has a small one (order 1 eV), and an insulator has a large one — which is why heating a semiconductor increases its conductivity while heating a metal decreases it.
Binding energy and mass defect
A bound nucleus weighs less than its constituent nucleons; the missing mass is the binding energy through E=Δmc2E = \Delta mc^{2}, with 1 u=931.5 MeV/c21\ \mathrm{u} = 931.5\ \mathrm{MeV}/c^{2}. Binding energy per nucleon peaks near iron, which is why both fusion of light nuclei and fission of heavy ones release energy.
Half-life and decay constant
N(t)=N0eλtN(t) = N_0e^{-\lambda t} with t1/2=ln2/λ0.693/λt_{1/2} = \ln 2/\lambda \approx 0.693/\lambda and mean lifetime τ=1/λ\tau = 1/\lambda. Activity is A=λNA = \lambda N, so it decays with the same half-life as the population.

Intuition

Every spectral line is a subtraction. The atom does not emit its energy levels; it emits the difference between two of them, and that difference is the photon. Once that is automatic, the Balmer, Lyman, and Paschen series stop being lists to memorise and become the obvious consequence of which level the atom falls to.

Scaling beats computing. Hydrogen-like energies go as Z2/n2Z^{2}/n^{2} and radii as n2/Zn^{2}/Z; well energies go as 1/L21/L^{2}; X-ray cutoffs go as 1/V1/V; decay populations halve on a fixed clock. The exam builds items around these proportionalities precisely because they can be answered in one step, and a candidate who reaches for constants instead of ratios runs out of time rather than out of knowledge.

The nucleus and the solid are the same quantum story at different scales. Confinement produces discrete levels in an atom, bands in a crystal where the levels of 102310^{23} atoms smear together, and shell structure in nuclei. Recognising that a band gap and an atomic level spacing are the same kind of object turns condensed matter from a separate subject into a corollary.

Concept walkthrough

ETS lists atomic physics among the content areas of the GRE Physics Test, and our learning model additionally groups condensed-matter and nuclear material into this canonical domain — that grouping is our own reading of the outline, chosen because these specialised topics share a formalism, not because ETS labels them together. Practically, this is the block where breadth beats depth: a wide, shallow command of many standard results is worth far more than mastery of any one of them.

The Bohr model remains the exam's workhorse for one-electron systems. Its results are En=13.6Z2/n2 eVE_n = -13.6Z^{2}/n^{2}\ \mathrm{eV}, rn=n2a0/Zr_n = n^{2}a_0/Z with a0=0.0529 nma_0 = 0.0529\ \mathrm{nm}, and the emitted photon energy ΔE=13.6Z2(1nf21ni2) eV\Delta E = 13.6Z^{2}\left(\dfrac{1}{n_f^{2}}-\dfrac{1}{n_i^{2}}\right)\ \mathrm{eV}, equivalently the Rydberg formula 1λ=RZ2(1nf21ni2)\dfrac{1}{\lambda} = R_\infty Z^{2}\left(\dfrac{1}{n_f^{2}}-\dfrac{1}{n_i^{2}}\right) with R=1.097×107 m1R_\infty = 1.097\times10^{7}\ \mathrm{m^{-1}}. Transitions ending at nf=1n_f = 1 form the ultraviolet Lyman series, at nf=2n_f = 2 the visible Balmer series, and at nf=3n_f = 3 the infrared Paschen series. The ionisation energy of ground-state hydrogen is 13.6 eV13.6\ \mathrm{eV}, which is the single most useful number in the domain.

Quantum numbers organise multi-electron atoms even though the Bohr energies no longer apply. The set (n,,m,ms)(n, \ell, m_\ell, m_s) has =0,,n1\ell = 0,\ldots,n-1, m=,,+m_\ell = -\ell,\ldots,+\ell, and ms=±12m_s = \pm\tfrac{1}{2}; the Pauli exclusion principle forbids two electrons from sharing all four, so a subshell \ell holds 2(2+1)2(2\ell+1) electrons and a shell nn holds 2n22n^{2}. Electric-dipole transitions obey the selection rule Δ=±1\Delta\ell = \pm1, which is why not every energetically allowed transition actually appears in a spectrum. In a magnetic field the mm_\ell degeneracy splits with spacing μBB\mu_BB where μB=5.79×105 eV/T\mu_B = 5.79\times10^{-5}\ \mathrm{eV/T} — the Zeeman effect — and spin-orbit coupling produces fine structure at the scale α2(1/137)2\alpha^{2} \approx (1/137)^{2} relative to the gross level spacing.

X-rays connect atomic structure to crystals. Electrons accelerated through a potential VV strike a target; the continuous bremsstrahlung spectrum they produce cuts off sharply at λmin=hc/eV\lambda_{\min} = hc/eV, because no photon can carry more than the electron's whole kinetic energy. Superposed on it are characteristic lines from inner-shell vacancies, whose frequencies follow Moseley's law f(Z1)\sqrt{f} \propto (Z-1) for the KαK_\alpha line — historically the evidence that atomic number, not atomic weight, orders the elements. Sent into a crystal, X-rays reflect constructively when Bragg's condition 2dsinθ=mλ2d\sin\theta = m\lambda is met, where θ\theta is measured from the crystal plane rather than from its normal, and dd is the interplanar spacing.

Condensed matter on this exam is a small set of qualitative facts with a few numbers attached. Solids are classified by their band structure: metals have a partly filled band and conduct at any temperature, with resistivity rising as temperature increases because lattice vibrations scatter electrons more; semiconductors have a gap of order an electronvolt and conduct better when heated because more carriers are thermally excited across it; insulators have a gap far above kBTk_BT. The free-electron model gives a Fermi energy EF=22m(3π2n)2/3E_F = \dfrac{\hbar^{2}}{2m}(3\pi^{2}n)^{2/3} of a few electronvolts for typical metals, far above kBT0.025 eVk_BT \approx 0.025\ \mathrm{eV} at room temperature, which is why the electron gas is strongly degenerate and contributes far less to heat capacity than classical equipartition would predict. Lattice vibrations supply the rest, giving the Dulong-Petit value 3R3R per mole at high temperature and a T3T^{3} dependence at low temperature.

Nuclear physics closes the domain with conservation laws and one exponential. Decays conserve nucleon number and charge: alpha decay lowers AA by 4 and ZZ by 2; beta-minus decay converts a neutron into a proton, raising ZZ by 1 at fixed AA and emitting an electron and an antineutrino; beta-plus decay does the reverse; gamma decay changes neither. The binding energy comes from the mass defect, B=[Zmp+Nmnmnucleus]c2B = \left[Zm_p + Nm_n - m_{\text{nucleus}}\right]c^{2}, with 1 u=931.5 MeV/c21\ \mathrm{u} = 931.5\ \mathrm{MeV}/c^{2} and a binding energy per nucleon that rises steeply to about 8.8 MeV8.8\ \mathrm{MeV} near iron and then falls slowly — hence energy release from fusing light nuclei and from fissioning heavy ones. Decay itself is N(t)=N0eλtN(t) = N_0e^{-\lambda t}, but on a timed test the fastest route is almost always to count half-lives: after kk half-lives a fraction 2k2^{-k} remains.

After this page, you should be able to

  • Compute transition energies and photon wavelengths for hydrogen-like atoms and scale them correctly with ZZ and nn.
  • Apply the photoelectric relation, distinguish the effect of intensity from the effect of frequency, and find a stopping potential or threshold wavelength.
  • Assign quantum numbers, apply the Pauli exclusion principle, and count shell capacities and level degeneracies.
  • Use λmin=hc/eV\lambda_{\min} = hc/eV for an X-ray tube and Bragg's law 2dsinθ=mλ2d\sin\theta = m\lambda for crystal diffraction, with the angle measured from the plane.
  • Classify a solid from its band gap and predict the sign of its conductivity's temperature dependence.
  • Balance nuclear decay equations, compute binding energy from a mass defect, and solve exponential-decay problems using half-lives rather than logarithms wherever possible.

Formulas and assumptions

Hydrogen-like atoms

En=13.6Z2n2 eV,rn=n2a0Z,ΔE=13.6Z2 ⁣(1nf21ni2)eVE_n = -\frac{13.6\,Z^{2}}{n^{2}}\ \mathrm{eV}, \quad r_n = \frac{n^{2}a_0}{Z}, \quad \Delta E = 13.6Z^{2}\!\left(\frac{1}{n_f^{2}}-\frac{1}{n_i^{2}}\right)\mathrm{eV}

Variables

  • Z: nuclear charge number
  • n: principal quantum number
  • a0: Bohr radius, 0.0529 nm

Assumptions

  • Valid only for one-electron systems: H, He+, Li2+, and so on, never neutral multi-electron atoms.
  • Energies scale as Z^2/n^2 while radii scale as n^2/Z, so the two scalings run in opposite directions.

Photons, the photoelectric effect, and the stopping potential

E=hcλ,Kmax=hfϕ,λmax=hcϕ,eVstop=KmaxE = \frac{hc}{\lambda}, \qquad K_{\max} = hf - \phi, \qquad \lambda_{\max} = \frac{hc}{\phi}, \qquad eV_{\text{stop}} = K_{\max}

Variables

  • phi: work function of the metal
  • K_max: maximum kinetic energy of the ejected electron
  • V_stop: stopping potential

Assumptions

  • Intensity sets how many electrons are ejected; frequency alone sets their maximum energy.
  • Below the threshold frequency no electrons are ejected at any intensity.

Quantum numbers, shell capacity, and selection rules

0n1,m,gshell=2n2,Δ=±1,ΔEZeeman=μBB0 \le \ell \le n-1, \quad -\ell \le m_\ell \le \ell, \quad g_{\text{shell}} = 2n^{2}, \quad \Delta\ell = \pm 1, \quad \Delta E_{\text{Zeeman}} = \mu_B B

Variables

  • l: orbital angular momentum quantum number
  • mu_B: Bohr magneton, 5.79 x 10^-5 eV/T

Assumptions

  • The Pauli exclusion principle is what converts the quantum-number ranges into shell capacities.
  • The selection rule applies to electric-dipole transitions; forbidden transitions can still occur far more slowly.

X-ray production and Bragg diffraction

λmin=hceV,f(Z1),2dsinθ=mλ\lambda_{\min} = \frac{hc}{eV}, \qquad \sqrt{f} \propto (Z-1), \qquad 2d\sin\theta = m\lambda

Variables

  • V: accelerating potential of the X-ray tube
  • d: interplanar spacing of the crystal
  • theta: glancing angle, measured from the plane and not from its normal

Assumptions

  • The cutoff wavelength depends only on the tube voltage, never on the target material.
  • Bragg's angle convention differs from the optics convention, which is the usual source of a factor-of-two-looking error.

Solids: bands, Fermi energy, and heat capacity

EF=22m(3π2n)2/3,Clattice3R (high T),CT3 (low T)E_F = \frac{\hbar^{2}}{2m}\left(3\pi^{2}n\right)^{2/3}, \qquad C_{\text{lattice}} \to 3R \ (\text{high } T), \qquad C \propto T^{3}\ (\text{low } T)

Variables

  • n: conduction-electron number density
  • E_F: Fermi energy, a few eV for typical metals

Assumptions

  • E_F is far above k_B T at room temperature (0.025 eV), so the electron gas is degenerate and contributes little heat capacity.
  • The temperature dependence of conductivity has opposite signs for metals and semiconductors, which is the fastest way to tell them apart.

Nuclear binding, decay bookkeeping, and the exponential law

B=Δmc2,1 u=931.5 MeV/c2,N(t)=N0eλt,t1/2=ln2λ,τ=1λB = \Delta m\,c^{2}, \quad 1\ \mathrm{u} = 931.5\ \mathrm{MeV}/c^{2}, \quad N(t) = N_0e^{-\lambda t}, \quad t_{1/2} = \frac{\ln 2}{\lambda}, \quad \tau = \frac{1}{\lambda}

Variables

  • A: mass number (nucleon count); also used for activity, which context distinguishes
  • lambda: decay constant
  • tau: mean lifetime, longer than the half-life by 1/ln2 = 1.44

Assumptions

  • Binding energy per nucleon peaks near iron at about 8.8 MeV, which is why both fusion below it and fission above it release energy.
  • After k half-lives the surviving fraction is 2^-k; counting half-lives is faster and safer than taking logarithms.

Worked example

One constant, two scales: a Balmer photon and an X-ray in a crystal

(a) A hydrogen atom drops from n=3n = 3 to n=2n = 2. Find the photon energy and wavelength, and the corresponding values for He+\mathrm{He}^{+}. (b) An X-ray tube runs at 30 kV30\ \mathrm{kV}. Find the shortest wavelength it produces, and the first-order Bragg angle for that wavelength from crystal planes spaced d=0.20 nmd = 0.20\ \mathrm{nm} apart.

  1. 1Compute the two hydrogen levels: E3=13.6/9=1.511 eVE_3 = -13.6/9 = -1.511\ \mathrm{eV} and E2=13.6/4=3.400 eVE_2 = -13.6/4 = -3.400\ \mathrm{eV}. The photon carries the difference, ΔE=E3E2=1.511(3.400)=1.889 eV\Delta E = E_3 - E_2 = -1.511 - (-3.400) = 1.889\ \mathrm{eV}. It is positive because the atom drops to a more tightly bound level and releases the surplus.
  2. 2Convert to a wavelength with the constant that makes this a one-step division: λ=hcΔE=1240 eVnm1.889 eV=656 nm\lambda = \dfrac{hc}{\Delta E} = \dfrac{1240\ \mathrm{eV\,nm}}{1.889\ \mathrm{eV}} = 656\ \mathrm{nm} — the red H-alpha line, and a useful anchor for checking any Balmer calculation.
  3. 3Scale to He+\mathrm{He}^{+}, which is hydrogen-like with Z=2Z = 2. Every level scales by Z2=4Z^{2} = 4, so ΔE=4(1.889)=7.56 eV\Delta E = 4(1.889) = 7.56\ \mathrm{eV} and λ=656/4=164 nm\lambda = 656/4 = 164\ \mathrm{nm}, in the ultraviolet. No re-derivation is needed: the whole spectrum shifts by one factor.
  4. 4For the tube, an electron accelerated through 30 kV30\ \mathrm{kV} arrives with 3.0×104 eV3.0\times10^{4}\ \mathrm{eV} of kinetic energy, and the most energetic photon it can produce carries all of it. So λmin=hceV=1240 eVnm3.0×104 eV=0.0413 nm=41.3 pm\lambda_{\min} = \dfrac{hc}{eV} = \dfrac{1240\ \mathrm{eV\,nm}}{3.0\times10^{4}\ \mathrm{eV}} = 0.0413\ \mathrm{nm} = 41.3\ \mathrm{pm}. Note that this depends only on the voltage, not on the target element — the target only fixes where the characteristic lines sit.
  5. 5Apply Bragg's law for first order, m=1m = 1: sinθ=mλ2d=0.04132(0.20)=0.1033\sin\theta = \dfrac{m\lambda}{2d} = \dfrac{0.0413}{2(0.20)} = 0.1033, so θ=5.9\theta = 5.9^{\circ}. The angle is measured from the crystal plane, not from its normal — using the normal here would give 84.184.1^{\circ}, a wrong answer that is often among the options.
  6. 6Check the scales against each other. The visible photon has λ656 nm\lambda \approx 656\ \mathrm{nm} and the X-ray about 0.041 nm0.041\ \mathrm{nm} — a factor of roughly 16,00016{,}000, matching the energy ratio 3.0×104/1.8891.6×1043.0\times10^{4}/1.889 \approx 1.6\times10^{4}, as it must since λ1/E\lambda \propto 1/E. That reciprocal relation is the fastest consistency check available in this domain.

(a) Hydrogen 323\to2: ΔE=1.89 eV\Delta E = 1.89\ \mathrm{eV}, λ=656 nm\lambda = 656\ \mathrm{nm}; He+\mathrm{He}^{+}: ΔE=7.56 eV\Delta E = 7.56\ \mathrm{eV}, λ=164 nm\lambda = 164\ \mathrm{nm}. (b) λmin=41.3 pm\lambda_{\min} = 41.3\ \mathrm{pm} and the first-order Bragg angle is 5.95.9^{\circ} from the plane. Doubling the tube voltage halves λmin\lambda_{\min} and roughly halves the Bragg angle at these small angles.

Common traps

  • Applying En=13.6/n2 eVE_n = -13.6/n^{2}\ \mathrm{eV} to a multi-electron atom. The formula is exact only for one-electron systems, so neutral helium is out and He+\mathrm{He}^{+} is in.
  • Dropping the Z2Z^{2} when moving to a hydrogen-like ion, or scaling the radius by Z2Z^{2} instead of 1/Z1/Z. Energies and radii scale in opposite directions.
  • Reporting a level energy as the photon energy. The photon carries the difference between two levels, and its energy is always positive.
  • Confusing the shell capacity 2n22n^{2} with the subshell capacity 2(2+1)2(2\ell+1).
  • Measuring the Bragg angle from the normal to the planes. Bragg's law uses the glancing angle from the plane itself, unlike every optics convention.
  • Assuming the X-ray cutoff wavelength depends on the target material. It depends only on the accelerating voltage; the target sets the characteristic lines.
  • Expecting a semiconductor's conductivity to fall with temperature as a metal's does. It rises, because heating promotes carriers across the gap.
  • Confusing half-life with mean lifetime. τ=t1/2/ln21.44t1/2\tau = t_{1/2}/\ln 2 \approx 1.44\,t_{1/2}, so they differ by more than 40%.
  • Losing track of AA and ZZ in a decay chain. Alpha decay takes (A,Z)(A4,Z2)(A,Z) \to (A-4, Z-2); beta-minus takes (A,Z)(A,Z+1)(A,Z) \to (A, Z+1); gamma changes neither.
  • Adding free-nucleon masses and expecting the nuclear mass. The difference is the mass defect, and it is the binding energy — a bound nucleus is always lighter than its parts.

Question depth and domain coverage vary by exam. Practice answers are checked after submission.

Sources

  1. GRE Subject Test Content and StructureETS. Accessed 2026-07-06. Use as a cited source for exam facts; do not imply affiliation or reproduce protected test material.
  2. University Physics Volume 3, Section 6.2: Photoelectric EffectOpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
  3. University Physics Volume 3, Section 6.5: De Broglie's Matter WavesOpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
  4. University Physics Volume 3, Section 7.4: The Quantum Particle in a BoxOpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.

Sources and corrections

Sources last checked 2026-08-15

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