Question
A starship travels at relative to Earth. The crew measures between two ticks of a clock on board. How much time elapses between those same two ticks as measured by Earth observers?
- a.
- b.
- c.
- d.
Correct answer
B.
Full reasoning
- 1The crew's is the proper time , because both ticks occur at the clock's own location in the ship frame.
- 2Compute the Lorentz factor: .
- 3Earth observers measure the dilated interval .
Why each choice is right or wrong
Choice A
This uses without taking the square root in the denominator.
Choice B
Correct. , and the dilated interval is .
Choice C
This assumes both frames share a universal time; in special relativity the moving clock's interval is dilated for Earth observers.
Choice D
This divides by instead of multiplying, which would make the moving clock appear to run fast rather than slow.
Related formula
Time dilation
Assumptions: Both frames are inertial. The proper-time clock is present at both events.
Related topic and practice
This public explainer is separate from the protected practice bank. Current practice coverage varies.
Source and public-release record
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- University Physics Volume 3, Section 5.3: Time Dilation — OpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
Review and maintenance
Source-checked by publisher- Publisher record
- Keiko Study editorial owner
- Publisher placeholder; no individual credential claim is made yet.
- Reviewer record
- Technical reviewer pending
- Placeholder only; this content is not labeled as reviewed by a named specialist.
- Last source check
- 2026-08-07
- Next scheduled review
- 2026-11-07
Recheck the cited OpenStax reference before each major GRE Physics preparation cycle.