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Worked example

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Exponent Rules

A public exponents question that combines the power-of-a-product rule with the quotient rule to simplify an algebraic fraction.

Question

For x0x \neq 0, which expression equals (2x3)48x5\dfrac{(2x^3)^4}{8x^5}?

  1. a.2x72x^{7}
  2. b.x74\dfrac{x^{7}}{4}
  3. c.2x22x^{2}
  4. d.2x172x^{17}

Correct answer

A. 2x72x^{7}

Full reasoning

  1. 1Apply the power of a product rule: (2x3)4=24(x3)4(2x^3)^4 = 2^4 (x^3)^4.
  2. 2Apply the power rule to multiply exponents: 24(x3)4=16x122^4 (x^3)^4 = 16x^{12}.
  3. 3Apply the quotient rule: 16x128x5=168x125=2x7\dfrac{16x^{12}}{8x^{5}} = \dfrac{16}{8} x^{12-5} = 2x^{7}.

Why each choice is right or wrong

Choice A

Correct. (2x3)4=24x12=16x12(2x^3)^4 = 2^4 x^{12} = 16x^{12}, and dividing gives 168x125=2x7\tfrac{16}{8} x^{12-5} = 2x^{7}.

Choice B

This forgets to raise the coefficient 22 to the fourth power, leaving 2x122x^{12} in the numerator and producing 28x7\tfrac{2}{8}x^{7}.

Choice C

This adds the exponents in the power step, turning (x3)4(x^3)^4 into x3+4=x7x^{3+4} = x^{7} instead of multiplying to get x12x^{12}.

Choice D

This adds the exponents when dividing, computing x12+5x^{12+5} instead of subtracting to get x125x^{12-5}.

Related formula

Power of a product and quotient of powers

(ab)m=ambm,aman=amn(ab)^m = a^m b^m, \qquad \frac{a^m}{a^n} = a^{m-n}

Assumptions: The base in the quotient rule is nonzero so the division is defined.

Related topic and practice

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Sources

Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.

  1. Elementary Algebra 2e, Section 6.2: Use Multiplication Properties of ExponentsOpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY 4.0; attribute and avoid verbatim reuse beyond short cited references.
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Sources and corrections

Sources last checked 2026-08-07

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