Question
A block is released from rest at the top of a frictionless track and slides down through a vertical drop of . Taking , what is the block's speed at the bottom?
- a.
- b.
- c.
- d.
Correct answer
B.
Full reasoning
- 1Only gravity does work on the frictionless track, so mechanical energy is conserved: .
- 2The mass cancels from both sides, so the value never enters the answer.
- 3Solve for the speed: .
- 4The block reaches the bottom at , so choice B is correct.
Why each choice is right or wrong
Choice A
This is ; the factor of 2 that appears when solving was dropped.
Choice B
Correct. , independent of the mass.
Choice C
This equates to (dropping the one-half) and then never takes the square root, reporting itself.
Choice D
This is reported as a speed; the final square root was skipped entirely.
Related formula
Energy conservation for a gravity-only drop
Assumptions: Friction and air resistance are negligible. The object starts from rest.
Related topic and practice
This public explainer is separate from the protected practice bank. Current practice coverage varies.
Source and public-release record
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- University Physics Volume 1, Section 8.3: Conservation of Energy — OpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
Review and maintenance
Source-checked by publisher- Publisher record
- Keiko Study editorial owner
- Publisher placeholder; no individual credential claim is made yet.
- Reviewer record
- Technical reviewer pending
- Placeholder only; this content is not labeled as reviewed by a named specialist.
- Last source check
- 2026-08-07
- Next scheduled review
- 2026-11-07
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