Question
A block is released from rest at the top of a frictionless track and slides down through a vertical drop of . Taking , what is the block's speed at the bottom?
- a.
- b.
- c.
- d.
Correct answer
B.
Full reasoning
- 1Only gravity does work on the frictionless track, so mechanical energy is conserved: .
- 2The mass cancels from both sides, so the value never enters the answer.
- 3Solve for the speed: .
- 4The block reaches the bottom at , so choice B is correct.
Why each choice is right or wrong
Choice A
This is ; the factor of 2 that appears when solving was dropped.
Choice B
Correct. , independent of the mass.
Choice C
This equates to (dropping the one-half) and then never takes the square root, reporting itself.
Choice D
This is reported as a speed; the final square root was skipped entirely.
Related formula
Energy conservation for a gravity-only drop
Assumptions: Friction and air resistance are negligible. The object starts from rest.
Related topic and practice
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Sources
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- University Physics Volume 1, Section 8.3: Conservation of Energy — OpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
Sources and corrections
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