Question
A lab technician has liters of a saline solution. How many liters of pure water must be added to dilute it to a saline solution?
- a. liters
- b. liters
- c. liters
- d. liters
Correct answer
C. liters
Full reasoning
- 1Adding pure water leaves the salt unchanged: the solution contains liters of salt throughout.
- 2Let be the liters of water added and set up the proportion for the target concentration: .
- 3Solve: , so liters.
- 4Check: liters of salt in liters of solution is , as required.
Why each choice is right or wrong
Choice A
This subtracts the percentage points, , and reads the difference as a volume, but percentage points are not liters.
Choice B
This scales the starting volume by , shrinking the batch instead of finding the extra water that grows the total to liters.
Choice C
Correct. The salt stays at liters, so gives and liters of added water.
Choice D
This solves correctly but reports the new total volume instead of subtracting the original liters.
Related formula
Dilution proportion with fixed solute
Assumptions: Only pure solvent is added, so the amount of solute never changes. Volumes are additive when the solvent is mixed in.
Related topic and practice
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Sources
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- Prealgebra 2e, Section 6.5: Solve Proportions and Their Applications — OpenStax. Accessed 2026-07-11. OpenStax textbook content is CC BY 4.0; attribute and avoid verbatim reuse beyond short cited references.
Sources and corrections
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