Question
A lab technician has liters of a saline solution. How many liters of pure water must be added to dilute it to a saline solution?
- a. liters
- b. liters
- c. liters
- d. liters
Correct answer
C. liters
Full reasoning
- 1Adding pure water leaves the salt unchanged: the solution contains liters of salt throughout.
- 2Let be the liters of water added and set up the proportion for the target concentration: .
- 3Solve: , so liters.
- 4Check: liters of salt in liters of solution is , as required.
Why each choice is right or wrong
Choice A
This subtracts the percentage points, , and reads the difference as a volume, but percentage points are not liters.
Choice B
This scales the starting volume by , shrinking the batch instead of finding the extra water that grows the total to liters.
Choice C
Correct. The salt stays at liters, so gives and liters of added water.
Choice D
This solves correctly but reports the new total volume instead of subtracting the original liters.
Related formula
Dilution proportion with fixed solute
Assumptions: Only pure solvent is added, so the amount of solute never changes. Volumes are additive when the solvent is mixed in.
Related topic and practice
This public explainer is separate from the protected practice bank. Current practice coverage varies.
Source and public-release record
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- Prealgebra 2e, Section 6.5: Solve Proportions and Their Applications — OpenStax. Accessed 2026-07-11. OpenStax textbook content is CC BY 4.0; attribute and avoid verbatim reuse beyond short cited references.
Review and maintenance
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- Last source check
- 2026-08-07
- Next scheduled review
- 2026-11-07
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