Question
A Carnot engine operates between a hot reservoir at and a cold reservoir at , absorbing of heat from the hot reservoir each cycle. How much work does it deliver per cycle?
- a.
- b.
- c.
- d.
Correct answer
C.
Full reasoning
- 1Carnot efficiency uses absolute temperatures: .
- 2The work per cycle is .
- 3Energy balance check: the rejected heat is , which matches for a reversible cycle.
Why each choice is right or wrong
Choice A
This assumes complete conversion of the absorbed heat into work, which the second law forbids for any cyclic engine.
Choice B
This is the heat rejected to the cold reservoir, , mistakenly reported as the work output.
Choice C
Correct. , so .
Choice D
This comes from the incorrect efficiency formula ; the denominator should be alone.
Related formula
Carnot efficiency
Assumptions: Both temperatures are expressed in kelvin. The engine runs a reversible Carnot cycle between the two reservoirs.
Related topic and practice
This public explainer is separate from the protected practice bank. Current practice coverage varies.
Source and public-release record
Authored for this public explainer registry. It has no database question ID and is not copied from a protected or official exam bank.
- University Physics Volume 2, Section 4.5: The Carnot Cycle — OpenStax. Accessed 2026-08-02. OpenStax textbook content is CC BY-NC-SA 4.0; attribute and avoid verbatim reuse beyond short cited references.
Review and maintenance
Source-checked by publisher- Publisher record
- Keiko Study editorial owner
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- Reviewer record
- Technical reviewer pending
- Placeholder only; this content is not labeled as reviewed by a named specialist.
- Last source check
- 2026-08-07
- Next scheduled review
- 2026-11-07
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